Math Test Set 12

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1. If y varies inversely as x and y = 8 when x = 3, find the value of x when y = 12.

A.8

B.-8

C.2

D.-2

Question 1 of 10

2. Given the following set of numbers {1,2,3,4,5,6,7,8,9,10} what is the probability of choosing an even number, given that a multiple of 3 is chosen?

A.\(\frac{1}{2}\)

B.\(\frac{1}{3}\)

C.0

D.\(\frac{3}{4}\)

Question 2 of 10

3. Factor. \(6x^{2} - 19x +10\)

A.(3x − 10)(2x + 1)

B.(6x − 5)(x − 2)

C.(3x − 5)(2x − 2)

D.(3x − 2)(2x − 5)

Question 3 of 10

4. Emily orders two cheese pizzas from Toni's Pizza for herself and some friends. However, Toni's Pizza accidentally put some sausage on a few of the slices of each pizza (shown in the pictures as the shaded slices). The sausage is not visible when just looking at the slice of pizza. Given that one of Emily's friends grabs the pizza containing the three slices of sausage, leaving only the other pizza for Emily to choose from, what is the probability that Emily chooses a slice of sausage pizza?

A.\( \frac{1}{4}\)

B.\( \frac{1}{2}\)

C.\( \frac{5}{16}\)

D.\( \frac{6}{16}\)

Question 4 of 10

Math-Solution of equations

5. Which of the numbers following the given equation is a solution of the given equation?

x − 3 = 6; 9, 16, 10, 12

A.9

B.3

C.1

D.8

Question 5 of 10

Math-Distributive Property

6. Use the distributive property to expand the given expression.

\(9(−2b^{2} + 2b + 9)\)

A.\(−18b^{2} + 18b + 81 \)

B.\(18b^{2} + 18b + 81 \)

C.\(-18b^{2} - 18b + 81 \)

D.\(-18b^{2} + 18b + 21 \)

Question 6 of 10

Math-Word problems

7. The number −10 is −5 times larger than an unknown number. Find the unknown number.

A.2

B.-2

C.4

D.-3

Question 7 of 10

Math- Equations

8. Solve the equation.

2(7 − 9x) − (2x − 8) = 7

A.\(\frac{3}{4}\)

B.\(\frac{4}{3}\)

C.1

D.\(\frac{4}{5}\)

Question 8 of 10

Math-Percent to decimal

9. Convert the given percent to a decimal.

0.6379%

A.0.006379

B.63,79

C.0.6379

D.6.379

Question 9 of 10

Math-Evaluate expression

10. Evaluate the expression at the given values of x and y.

|x − y| at x = 4 and y = 4

A.0

B.1

C.-1

D.2

Question 10 of 10

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